DyLab_3D_MOT/Cooling/02_implement_power_equality.py
2021-10-01 14:37:07 +02:00

70 lines
1.7 KiB
Python

# -*- coding: utf-8 -*-
"""
Created on Mon Sep 20 11:41:53 2021
@author: Joschka
"""
import matplotlib.pyplot as plt
import numpy as np
#from src import B_field_calculation as bf
from src import coil_class as BC
from src import physical_constants as cs
from IPython import get_ipython
get_ipython().run_line_magic('matplotlib', 'qt')
#get_ipython().run_line_magic('matplotlib', 'inline')
#set up constants
#h_air =10 #Heat transfer with air W/m^2 K
e_cu = 3e-2 #emissivity copper, polished
rho_cu = 1.7*1e-8
I = 10 #A
#set up axis
x = np.linspace(-50, 50, 10001)
z = np.linspace(-50, 50, 10001)
AHH_opt = BC.BCoil(HH = -1, distance = 81.8 ,radius = 46.875 ,layers = 4, windings = 4 , wire_width= 1, wire_height= 2 ,layers_spacing = 0.25, windings_spacing= 0.25)
h = AHH_opt.get_coil_height()
w = AHH_opt.get_coil_width()
print(h)
print(w)
vert_surf = h * AHH_opt.radius * 2 *np.pi
hor_surf = np.pi*(AHH_opt.get_R_outer()**2-AHH_opt.get_R_inner()**2)
S_coil = 2*vert_surf + 2*hor_surf
#S_coil = S_coil/2
print(f"Surface area = {S_coil}")
def power_bal(T,h_air):
T_0 = 22.5
f = h_air * S_coil *(T-T_0) - 0.5*AHH_opt.power(I, T)
return f
print(e_cu * S_coil * cs.sigma_B**4 * (50**4 - 22.5**4))
T = np.linspace(20,120,500)
T_calc = np.linspace(20,2200,1000)
for h_air in [2.5,10,25]:
pos_min = np.argmin(np.abs(power_bal(T_calc,h_air)))
T_SS = T_calc[pos_min]
print(f"T_ss = {T_SS} °C")
plt.plot(T,power_bal(T,h_air),label = f"$h_{{air}} = {h_air} \; W/m^2 K$ , $T_{{SS}}$ = {T_SS:.2f}°C")
plt.ylabel("Power balance [W]")
plt.xlabel("temparature [°C]")
plt.title(f"Power balance, free convection, AHH coil, I = {I} A, windings: 4 x 4")
plt.legend()
plt.show()
print(AHH_opt.power(I, 25)/2)